The oxidation number of nitrogen in the compound is +4. Q. Among the oxides of nitrogen: N2O3, N2O4 and N2O5 ; the molecule(s) having nitrogen-nitrogen bond is/are: (A) Only N2O5 (B) N2O3 and N2O5 (C) N2O4 and ... Mark the element which shows only one oxidation state in its compounds. d. NO. In which of the following is the oxidation state of nitrogen given incorrectly? Reacts with water and produce nitric (HNO 3) acid. c. N2O4. b. N2O3. It is Anhydrate of nitiric acid. 2 Answers. B. a. N2O. Nitrogen compounds, on the other hand, encompass oxidation states of nitrogen ranging from -3, as in ammonia and amines, to +5, as in nitric acid. The necessary steps required to show the formation of C C l 4 by Lewis electron dot diagram has been jumbled. BHU 1988. NH3 is a hydride of N and is highly stable and non-poisonous. Assertion: N 2 O 3 is Less Basic than P 2 O 3. Nitrogen shows a variety of oxidation states like +1(N2O), +2(NO), +3(N2O3), +4(N2O4), +5(N2O5), -1(NH2OH). Nitrogen has an oxidation number of +3 while NO 2 is a gas in brown colour. 9 4 O is : View Answer The compound Y b B a 2 C u 3 O 7 , which shows superconductivity has copper in oxidation state x , then x is : 9 years ago. Answer Save. a. HNO(+3) b. N2O3 (+3) c. NaN3 (-1) d. H2N2O2 (+1) e. N2H4 (-2) Therefore, the answer is 4. The N 2 O 3 molecule is planar and exhibits Cs symmetry. | EduRev Class 12 Question is disucussed on EduRev Study Group by 140 Class 12 Students. Anonymous. (a) Thus, an electron pair is shared between C and C l.This is the Lewis electron dot diagram for C C l 4 . Answer to Determine the oxidation state of nitrogen in each of the following. O usually has an oxidation number of -2. Dinitrogen trioxide, however, has an unusually long N–N bond at 186 pm. Reason: As we go down the group, the metallic nature increases. Favorite Answer. The dimensions displayed below come from microwave spectroscopy of low-temperature, gaseous N 2 O 3: The following table lists some of the known organic compounds of nitrogen, having different oxidation states of that element. Jan 06,2021 - The correct order of acidic strength of oxide of nitrogen isa)NO < NO2 < N2O < N2O3 < N2O5b)N2O < NO < N2O3 < N2O4 < N2O5c)NO < N2O < N2O3 < N2O5 < N2O4d)NO < N2O < N2O5 < N2O3 < N2O4Correct answer is option 'B'. (b) Write the symbol of chlorine and represent its valence electrons with the help of crosses, that is, SuperSpiderSoup2424. Dinitrogen dioxide is a white solid which sublimes at 32 0 C. N 2 O 5 is a good oxidizing agent because the oxidation state of nitrogen in this oxide being +5. In the equation N203, one should focus on the structure of the compounds. Can you explain this answer? There are 3 oxygen atoms with 2 electrons required to achieve a stab le octet. The sum of the oxidation numbers in a compound must equal 0. 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